The number of possible isomers for compound `C_(2) H_(3) Cl_(2) Br` is

Options

A. 2
B. 3
C. 4
D. 5

Explanation

To determine the number of possible isomers for the compound \( C_2H_3Cl_2Br \), we will follow these steps:

### Step 1: Determine the molecular formula
The given molecular formula is \( C_2H_3Cl_2Br \). This indicates that the compound contains:
- 2 Carbon (C) atoms
- 3 Hydrogen (H) atoms
- 2 Chlorine (Cl) atoms
- 1 Bromine (Br) atom

### Step 2: Identify the structure
Since we have two carbon atoms, we can consider the possible arrangements of the halogen atoms (Cl and Br) around the carbon skeleton. The carbon atoms can be arranged in a straight chain (C-C) since there are only two carbon atoms.

### Step 3: Consider the possible isomers
1. **Structural Isomers**: These arise from different connectivity of atoms. For \( C_2H_3Cl_2Br \), we can have:
- Both Cl atoms on one carbon and Br on the other: \( CH_2Cl_2-CHBr \)
- One Cl on each carbon: \( CHCl-CHClBr \)
- One Cl on one carbon and Br on the other carbon with the other Cl on the same carbon as Br: \( CHCl_2-CHBr \)

2. **Geometric Isomers**: Since we have two different halogens, we can also consider the spatial arrangement of the atoms. However, in this case, the compound does not have double bonds or rings that would allow for geometric isomerism.

### Step 4: Count the isomers
From the arrangements considered, we can summarize the possible isomers:
1. **Isomer 1**: \( CH_2Cl_2-CHBr \)
2. **Isomer 2**: \( CHCl-CHClBr \)
3. **Isomer 3**: \( CHCl_2-CHBr \)
4. **Isomer 4**: \( CH_2Cl-CHBrCl \)

Thus, we find that there are a total of **4 isomers** for the compound \( C_2H_3Cl_2Br \).

### Final Answer
The number of possible isomers for the compound \( C_2H_3Cl_2Br \) is **4**.

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