The total number of acyclic isomers, including the stereoisomers, with formula `C_(4)H_(7)Cl` is

Options

A. `{:("Geometrical" ,, "Optical") , (6 ,,2):}`
B. `{:("Geometrical" ,, "Optical") , (4 ,,2):}`
C. `{:("Geometrical" ,, "Optical") , (6 ,,0):}`
D. `{:("Geometrical" ,, "Optical") , (4 ,,0):}`

Answer

A

Explanation

`CH_(3) - CH_(2) - CH = CHCl` (cis and trans form)
`CH_(3)- CH = CH - CH_(2) Cl` (cis and trans form)
`CH_(3) - CH = C - Cl - CH_(3)` (cis and trans form)
`H_(2) = underset(CH_(3))underset(|)( C) - CH_(2) - Cl` (No stereo-isomers)
`H_(2) C = CH -overset(H)overset(|) underset(Cl)underset(|)( C^(**)) - CH_(3)` (2 optical isomers)