The number of stereoisomer possible for the following compound is `CH_(3) - CH = CH - CH (Br) - CH_(2) - CH_(3)`

Options

A. 2
B. 3
C. 4
D. 8

Explanation

To determine the number of stereoisomers for the compound `CH₃ - CH = CH - CH(Br) - CH₂ - CH₃`, we need to analyze the structure of the compound and identify the presence of chiral centers and double bonds.

### Step 1: Identify the double bond and its configuration
The compound has a double bond between the second and third carbon atoms (C2 and C3). This double bond can exist in two configurations: cis (Z) and trans (E).

### Step 2: Identify the chiral centers
Next, we need to check for chiral centers. A chiral center is a carbon atom that is attached to four different groups. In the given compound, we have:

- C4 (the carbon attached to the Br atom) is a chiral center because it is attached to four different groups:
1. Br
2. CH₂ (the next carbon in the chain)
3. CH (the carbon with the double bond)
4. CH₃ (the terminal carbon)

### Step 3: Count the stereoisomers
1. **Cis-Trans Isomers**: For the double bond (C2=C3), we can have two configurations: cis and trans.
2. **Chiral Center**: The presence of one chiral center (C4) allows for two configurations (R and S).

### Step 4: Calculate the total number of stereoisomers
The total number of stereoisomers can be calculated using the formula:
\[ \text{Total Stereoisomers} = 2^n \times m \]
where:
- \( n \) = number of chiral centers
- \( m \) = number of double bonds that can exhibit cis-trans isomerism

In our case:
- \( n = 1 \) (one chiral center at C4)
- \( m = 2 \) (two configurations for the double bond)

Thus, the total number of stereoisomers is:
\[ \text{Total Stereoisomers} = 2^1 \times 2 = 2 \times 2 = 4 \]

### Final Answer
The total number of stereoisomers possible for the compound `CH₃ - CH = CH - CH(Br) - CH₂ - CH₃` is **4**.

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