The energy of one mole of photons of radiation of wavelength 300 nm is
(Given: `h=6.63 xx 10^(-34) J s, N_A = 6.02 xx 10^23"mol"^(-1), c=3xx10^8 ms^-1`)

Options

A. 235 `"kJ mol"^(-1)`
B. 325 `"kJ mol"^(-1)`
C. 399 `"kJ mol"^(-1)`
D. 435 `"kJ mol"^(-1)`

Explanation

To find the energy of one mole of photons of radiation with a wavelength of 300 nm, we can use the formula:

\[ E = \frac{N_A \cdot h \cdot c}{\lambda} \]

Where:
- \(E\) = energy of one mole of photons (in joules)
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