Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is

Options

A. 2-pentene
B. proponaldehyde
C. 2-butene
D. 4-methylpent-2-ene

Explanation

To solve the problem step by step, we will analyze the transformations of Hex-4-ene-2-ol through the reactions mentioned.

### Step 1: Identify Hex-4-ene-2-ol
Hex-4-ene-2-ol is a six-carbon chain with a double bond at the 4th position and a hydroxyl (-OH) group at the 2nd position. The structure can be represented as follows:

```
CH3-CH-CH=CH-CH2-CH3
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