The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750 `Omega`. If the conductivity of 0.01M KCl solution at 298 K is `0.152 xx 10^(-3)"S cm"^(-1)`, then the cell constant of the conductivity cell is ___________`xx10^(-3)cm^(-1)`.

Explanation

To find the cell constant of the conductivity cell, we can use the relationship between resistance, conductivity, and the cell constant. The formula we will use is:

\[ R = \frac{L}{A \cdot \kappa} \]

Where:
- \( R \) is the resistance of the cell (in ohms, \( \Omega \))
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