When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is __________g.

Explanation

To solve the problem, we need to determine the mass of acetic acid adsorbed per gram of charcoal. Here’s the step-by-step solution:

### Step 1: Calculate the initial moles of acetic acid
We start with 200 mL of a 0.2 M acetic acid solution.

\[ \text{Moles of acetic acid} = \text{Molarity} \times \text{Volume (in L)} \]
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