Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _________.

Explanation

To solve the problem regarding the disproportionation of Manganese (VI) in acidic solution, we can follow these steps:

### Step 1: Understand the Disproportionation Reaction
Manganese (VI), which has an oxidation state of +6, can disproportionate in acidic solution. This means that it can simultaneously be oxidized and reduced to form two different oxidation states.

### Step 2: Identify the Products of Disproportionation
In acidic conditions, Manganese (VI) typically disproportionates to form Manganese (IV) and Manganese (VII). Therefore, the two ions formed are:
- Mn in +4 oxidation state (MnO2)
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