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0.2 g of an organic compound was subject...

0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of `N_2` evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is __________. [nearest integer]
(Given: Molar mass of `N_2` is 28 g `"mol"^(-1)`, Molar volume of `N_2` at STP : 22.4L)

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To find the percentage of nitrogen in the organic compound, we will follow these steps: ### Step 1: Convert the volume of nitrogen gas evolved from mL to L The volume of nitrogen gas evolved is given as 22.400 mL. We need to convert this to liters since the molar volume is given in liters. \[ \text{Volume in L} = \frac{22.400 \text{ mL}}{1000} = 0.0224 \text{ L} \] ...
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