If A dice is rolled till 6 comes , then probability of `P((x ge 5)/(x ge 2))` is

x ge 3, y ge 2

A fair die is tossed until six is obtained on it. Let X be the number of required tosses, then the conditional probability P(X ge5 X |gt 2) is :

The mean and variance of a random variable X having a binomial probability distribution are 6 and 3 respectively, then the probabiltiy P(X ge 2) is

If two loaded dice each have the property yjsy 2 or 4 is there times as likely to appears as 1,3,5,or6 on each roll. When two such dice are rolled, the probability of obtaining a total of 7 is p, then value of [1//p] is, where [x] represents the greatest integer less than or euqal to x.

If two loaded dice each have the property that 2 or 4 is three xx as likely to appear as 1,3,5, or 6 on each roll.When two such dice are rolled,the probability of obtaining a total of 7 is p, then the value of [1/p] is,where [x] represents the greatest integer less than or equal to x.

Let X be the number of successes in 'n' independent Bernoulli trials with probability of success p=(3)/(4) , the least value of 'n' so that P(x ge 1) ge 0.9375 is