if given `(x-1)/2=(y+1)/4=(z-1)/3` & `(2x-1)/5=(y-2)/3=z/6` then the shortest length between two lines is

Statement 1: The shortest distance between the lines x/2=y/(-1)=z/2 and (x-1)/(-2)=(y-1)/-2=(z-1)/4 is sqrt(2) . Statement 2: The shortest distance between two parallel lines is the perpendicular distance from any point on one of the lines to the other line.

Points (1,-1,2) is the foot of perpendicular drawn from point (0,3,1) on the line (x-a)/l=(y-2)/3=(z-b)/4 find the shortest distance between this line and the line (x-1)/3=(y-2)/4=(z-3)/5

(x)/(1)=y/1=(z)/(-1) " and " (x)/(3) =(y)/(4)=(z)/(5) Find the angle between the lines .

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

If the lies (x-3)/(1)=(y+2)/(-1)=(z+lambda)/(-2) lies on the line,2x-4y+3z=2, then the shortest distance between this line and the line,(x-1)/(12)=(y)/(9)=(z)/(4) is (A) 0 (B) 2 (C) 1 (D) 3

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3)and(x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

(x-4)/(3) =(y+1)/(4) =(z-6)/(5) " and " (x-5)/(1)=(2y+5)/(-2) =(z-3)/(1) Find angle between the lines