In circle (x-alpha)^2+(y-beta)^2=50 and ...

In circle `(x-alpha)^2+(y-beta)^2=50` and line `x+y=0` intersect at only one point `P` from origin is `4sqrt2` then `alpha^2+beta^2` is

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Consider a circle (x-alpha)^(2)+(y-beta)^(2)=50 ,where alpha,beta>0 .If the circle touches the line y+x=0 at the point "P" ,whose distance from the origin is 4sqrt(2) ,then (alpha+beta)^(2) is equal to

Equation of tangent to circle (x-alpha)^2+(y-beta)^2=50 is x+y=0 . Find (alpha+beta)^2

Consider the equation of a pair of straight lines as x^2-3xy+lambday^2+3x=5y+2=0 The point of intersection of line is (alpha, beta) , then the value of alpha^2+beta^2 is

A variable line ax+by+c=0 , where a, b, c are in A.P. is normal to a circle (x-alpha)^2+(y-beta)^2=gamma , which is orthogonal to circle x^2+y^2-4x-4y-1=0 .The value of alpha + beta+ gamma is equal to

The graphs of the equations 3x + y - 5 = 0 and 2x - y = 0 intersect at the point P (alpha,beta) . What is the value of (3alpha + beta) ?

The graph of the equations 5x- 2y + 1 = 0 and 4y- 3x +5 =0, intersect at the point P(alpha,beta) . What is the value of (2 alpha- 3 beta) ?

The graphs of the equations 3x + y- 5 = 0 and 2x - y - 5 = 0 intersect at the point P(alpha,beta) . What is the value of (3 alpha+ beta) ?

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The graph of the equations 5x-2y+1=0 and 4y-3x+5=0, intersect at the point P (alpha, beta) . What is the value of (2 alpha-3 beta) ? समीकरण 5x-2y+1=0 और 4y-3x+5=0 के आरेख एक-दूसरे को बिंदु P (alpha, beta) पर काटते हैं | (2 alpha-3 beta) का मान क्या होगा ?

If a circle having centre at (alpha,beta) radius r completely lies with in two lines x+y=2 and x+y=-2, then, min. (|alpha+beta+2|,|alpha+beta-2| is

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