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An ellipse frac{x^2}{a^2}+frac{y^2}{b^2}...

An ellipse `frac{x^2}{a^2}+frac{y^2}{b^2}=1` (a> b) whose eccentircity is `frac{1}{sqrt 2}` and passes through the focus of the parab whose vertex is (2, 3) and directrix is `2x + y - 6 = 0` then the length of the latus rectum of ellipse is

A

`sqrt (656)`

B

frac{sqrt (656)}{5}`

C

frac{sqrt (656)}{10}`

D

frac{sqrt (656)}{2}`

Text Solution

Verified by Experts

The correct Answer is:
B
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