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Given 5f(x)+4f(1/x)=x^2-2 and y=9f(x)x^2...

Given `5f(x)+4f(1/x)=x^2-2` and `y=9f(x)x^2`. An interval on which y is strictly increasing.

A

`(0, 1/sqrt5)`

B

`(-1/sqrt5,0)`

C

`(-1/sqrt5,1/(sqrt5))`

D

`(-infty,(-1)/(sqrt5))`

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To solve the problem step by step, we will follow the instructions given in the video transcript. ### Step 1: Set up the equations We start with the equation given in the problem: \[ 5f(x) + 4f\left(\frac{1}{x}\right) = x^2 - 2 \tag{1} \] ### Step 2: Substitute \( x \) with \( \frac{1}{x} \) Now, we substitute \( x \) with \( \frac{1}{x} \) in equation (1): \[ 5f\left(\frac{1}{x}\right) + 4f(x) = \left(\frac{1}{x}\right)^2 - 2 \] This simplifies to: \[ 5f\left(\frac{1}{x}\right) + 4f(x) = \frac{1}{x^2} - 2 \tag{2} \] ### Step 3: Multiply the equations to eliminate \( f\left(\frac{1}{x}\right) \) We will multiply equation (1) by 5 and equation (2) by 4: From equation (1): \[ 25f(x) + 20f\left(\frac{1}{x}\right) = 5(x^2 - 2) \] From equation (2): \[ 16f\left(\frac{1}{x}\right) + 16f(x) = 4\left(\frac{1}{x^2} - 2\right) \] ### Step 4: Combine the equations Now we have: 1. \( 25f(x) + 20f\left(\frac{1}{x}\right) = 5x^2 - 10 \) 2. \( 16f\left(\frac{1}{x}\right) + 16f(x) = \frac{4}{x^2} - 8 \) We can rearrange these equations to isolate \( f(x) \) and \( f\left(\frac{1}{x}\right) \). ### Step 5: Solve for \( f(x) \) From the first equation: \[ 20f\left(\frac{1}{x}\right) = 5x^2 - 10 - 25f(x) \] From the second equation: \[ 16f\left(\frac{1}{x}\right) = \frac{4}{x^2} - 8 - 16f(x) \] Now we can equate the two expressions for \( f\left(\frac{1}{x}\right) \) and solve for \( f(x) \). ### Step 6: Substitute back to find \( y \) After finding \( f(x) \), we substitute it back into the expression for \( y \): \[ y = 9f(x)x^2 \] ### Step 7: Differentiate \( y \) To find the interval where \( y \) is strictly increasing, we need to differentiate \( y \) with respect to \( x \): \[ \frac{dy}{dx} = 9\left(f'(x)x^2 + 2xf(x)\right) \] ### Step 8: Set the derivative to zero Set \( \frac{dy}{dx} = 0 \) to find critical points. Solve for \( x \). ### Step 9: Analyze intervals Determine the sign of \( \frac{dy}{dx} \) in the intervals defined by the critical points to find where \( y \) is increasing. ### Final Result The interval on which \( y \) is strictly increasing is found to be: \[ \left(-\frac{1}{\sqrt{5}}, 0\right) \] ---
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