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2 and 6 are roots of the equation ax^2 +...

2 and 6 are roots of the equation `ax^2 + bx + 1 = 0` then the quaratic equation whose roots are `1/(a + 3b)` and `1/(a + 6b)` is

A

`1081x^2 + 840 x- 144 = 0`

B

`1081x^2 + 840 x + 144 = 0`

C

`1081x^2 - 840 x + 144 = 0`

D

`1081x^2 - 840 x - 144 = 0`

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The correct Answer is:
B
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