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Let f(x) = x^5 + 2e^(x/4) AA x in R. Con...

Let `f(x) = x^5 + 2e^(x/4) AA x in R`. Consider a function of (gof) `(x) = x, AA x in R` then the value of 8g' (2) is

A

2

B

4

C

8

D

16

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The correct Answer is:
To solve the problem, we need to find the value of \(8g'(2)\) given the function \(f(x) = x^5 + 2e^{x/4}\) and the composition \(g(f(x)) = x\). ### Step-by-Step Solution: 1. **Differentiate the Composition**: We start with the equation: \[ g(f(x)) = x \] We differentiate both sides with respect to \(x\): \[ g'(f(x)) \cdot f'(x) = 1 \] From this, we can express \(g'(f(x))\) as: \[ g'(f(x)) = \frac{1}{f'(x)} \] 2. **Find \(g'(2)\)**: To find \(g'(2)\), we need to find \(x\) such that \(f(x) = 2\). We set: \[ f(a) = a^5 + 2e^{a/4} = 2 \] We need to solve this equation for \(a\). 3. **Check for \(a = 0\)**: Let's check if \(a = 0\) satisfies the equation: \[ f(0) = 0^5 + 2e^{0/4} = 0 + 2 \cdot 1 = 2 \] Thus, \(f(0) = 2\), so \(a = 0\) is a solution. 4. **Substitute \(a = 0\) into \(g'\)**: Since \(f(0) = 2\), we can substitute \(a = 0\) into our expression for \(g'\): \[ g'(2) = g'(f(0)) = \frac{1}{f'(0)} \] 5. **Find \(f'(x)\)**: Now, we need to compute \(f'(x)\): \[ f'(x) = 5x^4 + 2 \cdot \frac{1}{4} e^{x/4} = 5x^4 + \frac{1}{2} e^{x/4} \] Now, substituting \(x = 0\): \[ f'(0) = 5 \cdot 0^4 + \frac{1}{2} e^{0/4} = 0 + \frac{1}{2} \cdot 1 = \frac{1}{2} \] 6. **Calculate \(g'(2)\)**: Now we can find \(g'(2)\): \[ g'(2) = \frac{1}{f'(0)} = \frac{1}{\frac{1}{2}} = 2 \] 7. **Calculate \(8g'(2)\)**: Finally, we compute: \[ 8g'(2) = 8 \cdot 2 = 16 \] ### Final Answer: The value of \(8g'(2)\) is \(16\).
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