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Two companies A & B manufacture bikes. C...

Two companies A & B manufacture bikes. Company A manufacture 60% of bikes & B manufactures 40% of bikes, 80% bikes manufactured by company A are of super quality and other are of standard quality whereas 90% bikes manufactured by company B are of super quality and others are of standard quality. A bike is selected at random and found that it is of standard quality then find probability that bike is manufactured by company B.

A

`3/4`

B

`1/5`

C

`2/3`

D

`1/4`

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The correct Answer is:
To solve the problem, we need to find the probability that a randomly selected standard quality bike was manufactured by company B, given that it is a standard quality bike. We can use Bayes' theorem to find this probability. ### Step-by-Step Solution: 1. **Define Events:** - Let \( A \) be the event that the bike is manufactured by company A. - Let \( B \) be the event that the bike is manufactured by company B. - Let \( S \) be the event that the bike is of standard quality. 2. **Given Information:** - Probability of selecting a bike from company A: \[ P(A) = 0.6 \] - Probability of selecting a bike from company B: \[ P(B) = 0.4 \] - Probability of a standard quality bike from company A: \[ P(S|A) = 0.2 \quad (\text{since } 80\% \text{ are super quality, } 100\%-80\% = 20\%) \] - Probability of a standard quality bike from company B: \[ P(S|B) = 0.1 \quad (\text{since } 90\% \text{ are super quality, } 100\%-90\% = 10\%) \] 3. **Calculate Total Probability of Standard Quality Bikes:** Using the law of total probability, we can find \( P(S) \): \[ P(S) = P(A) \cdot P(S|A) + P(B) \cdot P(S|B) \] Substituting the values: \[ P(S) = (0.6 \cdot 0.2) + (0.4 \cdot 0.1) = 0.12 + 0.04 = 0.16 \] 4. **Apply Bayes' Theorem:** We want to find \( P(B|S) \), the probability that the bike is manufactured by company B given that it is of standard quality: \[ P(B|S) = \frac{P(B) \cdot P(S|B)}{P(S)} \] Substituting the values: \[ P(B|S) = \frac{0.4 \cdot 0.1}{0.16} \] 5. **Calculate the Result:** \[ P(B|S) = \frac{0.04}{0.16} = \frac{1}{4} \] ### Final Answer: The probability that a randomly selected standard quality bike was manufactured by company B is \( \frac{1}{4} \). ---
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