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The number of three digits numbers forme...

The number of three digits numbers formed by the number 2, 3, 4, 5, 7 without repetition which are not divisible by 3 is

A

24

B

36

C

12

D

48

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The correct Answer is:
To solve the problem of finding the number of three-digit numbers formed by the digits 2, 3, 4, 5, and 7 without repetition that are not divisible by 3, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Digits**: We have the digits 2, 3, 4, 5, and 7. This gives us a total of 5 digits. 2. **Calculate Total Three-Digit Numbers**: To form a three-digit number without repetition: - We can choose any of the 5 digits for the hundreds place. - For the tens place, we can choose from the remaining 4 digits. - For the units place, we can choose from the remaining 3 digits. Therefore, the total number of three-digit numbers is: \[ 5 \times 4 \times 3 = 60 \] 3. **Identify Numbers Divisible by 3**: A number is divisible by 3 if the sum of its digits is divisible by 3. We need to find combinations of three digits from our set that sum up to a number divisible by 3. - The digits are: 2, 3, 4, 5, 7. - Their remainders when divided by 3 are: - 2 % 3 = 2 - 3 % 3 = 0 - 4 % 3 = 1 - 5 % 3 = 2 - 7 % 3 = 1 - The remainders are: 2, 0, 1, 2, 1. We can find combinations of three digits whose sum is divisible by 3. The combinations are: - (2, 3, 4) → 2 + 3 + 4 = 9 (divisible by 3) - (2, 3, 5) → 2 + 3 + 5 = 10 (not divisible by 3) - (2, 3, 7) → 2 + 3 + 7 = 12 (divisible by 3) - (2, 4, 5) → 2 + 4 + 5 = 11 (not divisible by 3) - (2, 4, 7) → 2 + 4 + 7 = 13 (not divisible by 3) - (2, 5, 7) → 2 + 5 + 7 = 14 (not divisible by 3) - (3, 4, 5) → 3 + 4 + 5 = 12 (divisible by 3) - (3, 4, 7) → 3 + 4 + 7 = 14 (not divisible by 3) - (3, 5, 7) → 3 + 5 + 7 = 15 (divisible by 3) - (4, 5, 7) → 4 + 5 + 7 = 16 (not divisible by 3) The valid combinations that are divisible by 3 are: - (2, 3, 4) - (2, 3, 7) - (3, 4, 5) - (3, 5, 7) This gives us a total of 4 combinations. 4. **Calculate Numbers Divisible by 3**: Each combination can form \(3!\) (which is 6) different three-digit numbers since the digits can be arranged in any order. Therefore, the total number of three-digit numbers that are divisible by 3 is: \[ 4 \times 6 = 24 \] 5. **Calculate Numbers Not Divisible by 3**: To find the numbers that are not divisible by 3, we subtract the numbers that are divisible by 3 from the total three-digit numbers: \[ 60 - 24 = 36 \] ### Final Answer: The number of three-digit numbers formed by the digits 2, 3, 4, 5, and 7 without repetition that are not divisible by 3 is **36**.
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