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Let alpha = sum(r = 0)^n (4r^2 + 2r + 1)...

Let `alpha = sum_(r = 0)^n (4r^2 + 2r + 1)^nC_r` and `beta = sum_(r =0)^n` `("^nC_r)/(r + 1) + 1/(n+1)`, if `140 < (2 alpha)/(beta) < 248` then find n.

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JEE MAINS PREVIOUS YEAR-JEE MAIN 2024-Questions
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