Solve `3tan^(2) theta-2 sin theta=0`.

Answer

`theta=n pi, n pi +(-1)^(n) pi/6, n in Z`

Explanation

`tan^(2) theta-2 sin theta=0`
or `3(sin^(2) theta)/(cos^(2) theta)-2 sin theta=0, cos theta ne 0`
or `3 sin^(2) theta-2 sin theta (1- sin^(2) theta)=0`
or `3 sin^(2) theta-2 sin theta (1- sin^(2) theta)=0`
or `sin theta (2 sin^(2) theta+3 sin theta -2)=0`
or `sin theta (2 sin theta-1) (sin theta+2)=0`
or `sin theta=0, 1-2` (rejected)
`rArr theta=npi, n pi +(-1)^(n) pi/6, n in Z`