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Boron is unable to form BF(6)^(3-)– ion....

Boron is unable to form `BF_(6)^(3-)`– ion. Explain.

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Due to absence of d-orbitals, B at the maximum can ammoundates 8 electrons pairs of electrons in its valences shell. In other words, B can have a maximum convalency of 4. Therefore, `BF_(3)` can form `BF_(2)` but never `BF_(6)^(3-)` in which the covalency of B is 6.
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