Consider the compounds, `BCl_(3)` and `C Cl_(4)`.How will they behave with water? Justify.

Explanation

The B atom in `BCl_(3)` has only six electrons in the valence shell and hence is an electron-deficient molecule. It easily accepts a pair of electrons donated by water and hence `BCl_(3)` undergoes hydrolysis to form boric acid `(H_(3)BO_(3))` and HCl.
`BCl_(3) rarr + 3H_(2)O rarr H_(3)BO_(3) + 3HCl`
In contrast, C atom is `"CCl"_(4)` has 8 electrons in the valence shell. Therefore, it is an electron-precise molecule and hence neither accepts nor donates a pair of electrons. In other words , it does not accept a pair of electrons from `H_(2)O` molecule and hence `"CCl"_(4)` does not under go hydrolysis in water.