`PbCl_(2)` is insoluble in cold water. Addition of HCl increases its solubility due to

Options

A. formation of soluble complex anions like `[PbCl_(3)]^(-)`
B. oxidation of `Pb(II)` to `Pb(IV)`
C. formation of `[Pb(H_(2)O)_(6)]^(2+)`
D. formation of polymeric lead complexes

Answer

A

Explanation

Addition of `Cl^(-)` ion to a suspension of `PbCl_(2)` leads to the formation of soluble complex as shown below :
`underset(PbCl_(2))(PbCl_(2)) + Cl^(-) rarr underset(" Soluble complex ")([PbCl_(3)]^(-))`.