The reaction of chlorine water with propene gives

Options

A. `ClCH_(2)-CH(OH)CH_(3)`
B. `CH_(2)(OH)CH(Cl)CH_(3)`
C. `ClCH_(2)CH_(2)CH_(2)OH`
D. `ClCH(OH)CH_(2)CH_(3)ClCH(OH)CH_(2)CH_(3)`

Answer

To solve the question regarding the reaction of chlorine water with propene, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this case are propene (C3H6) and chlorine water (Cl2 dissolved in H2O).

2. **Structure of Propene**:
- Propene has the structure:
\[ CH2=CH-CH3 \]
- It contains a double bond between the first two carbon atoms.

3. **Reaction with Chlorine Water**:
- Chlorine water can generate hypochlorous acid (HOCl) when chlorine (Cl2) reacts with water (H2O).
- The reaction can be represented as:
\[ Cl_2 + H_2O \rightarrow HOCl + HCl \]

4. **Electrophilic Addition Mechanism**:
- The double bond in propene acts as a nucleophile and can react with the electrophile (the chlorine atom from HOCl).
- This is an electrophilic addition reaction.

5. **Markovnikov's Rule**:
- According to Markovnikov's rule, when HX (where X is a halogen) adds to an alkene, the halide (Cl in this case) will attach to the more substituted carbon atom.
- In propene, the more substituted carbon is the second carbon (the one bonded to two other carbon atoms).

6. **Formation of the Product**:
- The chlorine atom will attach to the second carbon, and a hydroxyl group (OH) will attach to the first carbon.
- The product formed will be:
\[ CH3-CH(Cl)-CH2(OH) \]
- This can also be written as:
\[ CH3-CHOH-CH2Cl \]

7. **Final Product**:
- The final product of the reaction of chlorine water with propene is 2-chloropropan-1-ol.

8. **Select the Correct Option**:
- Based on the options provided, we need to match our product (2-chloropropan-1-ol) with the given choices. The correct option will be the one that represents this compound.