A body of mass 500 g is suspended from the ceilling by a massless, inextensible and flexible string. A bullet of mass 10 g moving with velocity 300 m/s strikes the body herizontally and comes out horizontally with 200 m/s. Find the height to which the body will rise.

Explanation

Let `vecp and vecv` be the momentum and velocity respectively imparted to the body when the bullet moves through the body.
Applying conservation of linear momentum
`0.010xx300=0.0010xx200+p`
`impliesp=1kg ms^(-1)`
Applying conservation of energy between lowest point and highest point
`(P^(2))/(2m)+0mgh+0`
`impliesh=(P^(2))/(2m^(2)g)=(1)/(2xx(0.5)^(2)xx10)=(1m)/(5).0.2m`