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(x^(2)-y^(2))dx+2xydy=0...

`(x^(2)-y^(2))dx+2xydy=0`

Text Solution

Verified by Experts

The correct Answer is:
`x^(2)+y^(2)=Cx`
`(dy)/(dx)=(y^(2)-x^(2))/(2xy)`, which is homogeneous.
`int(2v)/(1+v^(2))dv=int-1/xdx rArr log|1+v^(2)|+log|x|=log|C|`.
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