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Solve : (x+y)dy+(y-2x)dx=0...

Solve : `(x+y)dy+(y-2x)dx=0`

Text Solution

Verified by Experts

The correct Answer is:
`y^(2)+2xy-2x^(2)=C`
`int(v+1)/(v^(2)+2v-2)dv=-int(dx)/(x) rArr 1/2 int (2v+2)/(v^(2)+2v-2) dv= -int (dx)/x`
`therefore 1/2log|v^(2)+2v-2|+log|x|=log|C_(1)|`.
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