Home
Class 12
MATHS
x(dy)/(dx)-y+xsin(y/x)=0...

`x(dy)/(dx)-y+xsin(y/x)=0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the homogeneous differential equation given by \[ x \frac{dy}{dx} - y + x \sin\left(\frac{y}{x}\right) = 0, \] we will follow a systematic approach. ### Step 1: Rearranging the Equation We can rearrange the equation to isolate \(\frac{dy}{dx}\): \[ x \frac{dy}{dx} = y - x \sin\left(\frac{y}{x}\right). \] Dividing both sides by \(x\) (assuming \(x \neq 0\)) gives us: \[ \frac{dy}{dx} = \frac{y}{x} - \sin\left(\frac{y}{x}\right). \] ### Step 2: Substitution Let \(v = \frac{y}{x}\). Then, we have \(y = vx\). Differentiating \(y\) with respect to \(x\) using the product rule gives: \[ \frac{dy}{dx} = v + x \frac{dv}{dx}. \] ### Step 3: Substituting into the Equation Substituting \(y = vx\) and \(\frac{dy}{dx}\) into our rearranged equation: \[ v + x \frac{dv}{dx} = v - \sin(v). \] ### Step 4: Simplifying the Equation We can simplify this equation: \[ x \frac{dv}{dx} = -\sin(v). \] ### Step 5: Separating Variables We can separate the variables: \[ \frac{dv}{-\sin(v)} = \frac{dx}{x}. \] ### Step 6: Integrating Both Sides Now we integrate both sides: \[ \int \frac{dv}{-\sin(v)} = \int \frac{dx}{x}. \] The left side can be integrated as: \[ -\ln|\csc(v) + \cot(v)| = \ln|x| + C, \] where \(C\) is the constant of integration. ### Step 7: Solving for \(y\) From the integration, we can express \(v\) in terms of \(x\): \[ \csc(v) + \cot(v) = \frac{1}{|x| e^{-C}}. \] Substituting back \(v = \frac{y}{x}\), we can express \(y\) in terms of \(x\). ### Final Solution The final solution will involve rearranging the above equation to find \(y\) explicitly in terms of \(x\). ---

To solve the homogeneous differential equation given by \[ x \frac{dy}{dx} - y + x \sin\left(\frac{y}{x}\right) = 0, \] we will follow a systematic approach. ...
Promotional Banner

Topper's Solved these Questions

  • HOMOGENEOUS DIFFERENTIAL EQUATION

    RS AGGARWAL|Exercise Exercise 20|30 Videos
  • FUNDAMENTAL CONCEPTS OF 3-DIMENSIONAL GEOMETRY

    RS AGGARWAL|Exercise Exercise|18 Videos
  • INDEFINITE INTEGRAL

    RS AGGARWAL|Exercise Objective Questions|41 Videos

Similar Questions

Explore conceptually related problems

Solve: x (dy)/(dx)- y-x tan . (y/x) . = 0

y -x (dy)/(dx) =0

Solve the following differential equations (x dy -y dx)y sin (y/x)= (y dx + x dy)x cos (y/x) .

If y=x log((x)/(a+bx)), thenx ^(3)(d^(2)y)/(dx^(2))= (a) x(dy)/(dx)-y (b) (x(dy)/(dx)-y)^(2)y(dy)/(dx)-x(d)(y(dy)/(dx)-x)^(2)

y-x(dy)/(dx)=x+y(dy)/(dx)

Solve: y-x(dy)/(dx)=x+y(dy)/(dx)

(xe^(y/x)-ysin(y/x))dx+xsin(y/x)dy=0

(dy)/(dx)+xsin2y=x^(3)cos^(2)y

The solution of xsin((y)/(x))dy={ysin((y)/(x))-x}dx, is given by

If xsin((y)/(x))dy=[ysin((y)/(x))-x]dx and y(1)=(pi)/(2) , then the value of cos((y)/(x)) is equal to