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If |{:(x,x+1),(x-1,x):}|=1, the find x (...

If `|{:(x,x+1),(x-1,x):}|=1,` the find x (x `in`R).

A

1

B

2

C

No real `x`

D

Any Real `x`

Text Solution

Verified by Experts

The correct Answer is:
D
We have
`|{:(x,x+1),(x-1,x):}|=1`
`x^2-(x+1)(x-1)=1`
`x^2-(x^2-1)=1`
`1=1`
`rArr" X "in` i.e., x can be any real value.
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