The solubility of Mg`(OH)_(2)` is `8.352xx10^(-3)` g/litre at `290^(@)` C. Find out its `K_(sp)` at this temperature.

Explanation

To find the solubility product constant (Ksp) of Mg(OH)₂ at 290°C given its solubility, we will follow these steps:

### Step 1: Write the dissociation equation
The dissociation of magnesium hydroxide in water can be represented as:
\[ \text{Mg(OH)}_2 (s) \rightleftharpoons \text{Mg}^{2+} (aq) + 2 \text{OH}^- (aq) \]

### Step 2: Define solubility
Let the solubility of Mg(OH)₂ be \( S \) (in mol/L). According to the dissociation equation:
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