Calculate the pH of a solution obtained by mixing 5 mL of 0.1 M `NH_(4)` OH with 250 mL of 0.1 M `NH_(4)` Cl solution . `K_(b)` for `NH_(4)OH=1.8xx10^(-5)`.

Explanation

To calculate the pH of the solution obtained by mixing 5 mL of 0.1 M `NH₄OH` with 250 mL of 0.1 M `NH₄Cl`, we can follow these steps:

### Step 1: Calculate the number of moles of `NH₄OH` and `NH₄Cl`
- For `NH₄OH`:
\[ \text{Moles of } NH₄OH = \text{Concentration} \times \text{Volume} = 0.1 \, \text{M} \times 0.005 \, \text{L} = 0.0005 \, \text{moles} \]

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