Three resistors of `5 Omega, 10 Omega and 15 Omega ` are connected in series and the combination is connected to battery of 30 V. Ammeter and Voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in proper correct order. What is the corrent flowing and potential difference across `10Omega` resistance?

Explanation

Current folowing, `I = ? , V_(2) = ? `
Total resistance , `R=R_(1) +R_(2) +R_(3)`
`=5+10+15=30 Omega`
Total potential difference, `V =30` volts
According to Ohm's law
`V=IR rArr I=(V)/(R ) =(30)/(30) =1` amp.
`because` Current remains constant in series
`therefore I_(1)=I_(2)=I_(3)=I " " I_(2) =1 " amp " R_(2) = 10 Omega " " V_(2)=?`
As `V_(2) = I_(2) R_(2) =1xx10 =10 ` volts.
`therefore " Potential difference across "10Omega " is 10 volts." `