Object distance, `u= -30 cm,` Focal length, `f = -30 cm`
(i) Lens formula, `1/f = 1/v - 1/u`
So `1/v = 1/f+1/u rArr 1/v= 1/-30+1/-30 =(1+1)/-30 = 2/-30`
`v= -15 cm`
The image distance is 15 cm in front of the lens.
(ii) Characteristics of image formed. The image is -
`*`virtual, " " `*` erect, " "`*`diminished,
`*` in front of the lens between 'O' and 'F', and
`*` 15 cm from the lens on the same side as the object
(iii)
