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If y = mx + c is a tangent to the circle...

If `y = mx + c` is a tangent to the circle `(x – 3)^2 + y^2 = 1` and also the perpendicular to the tangent to the circle `x^2 + y^2 = 1` at `(1/sqrt(2),1/sqrt(2))`, then

A

`c^(2)+6c+7=0`

B

`c^(2)-6c+7=0`

C

`c^(2)+7c+6=0`

D

`c^(2)-7c+6+0`

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The correct Answer is:
A
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