For a binomial distribution the mean is 6 and the standard deviation is `sqrt(2)`. Find the probability of getting 5 successes .

Answer

`.(9)C_(5).((2)/(3))^(5).((1)/(3))^(4)`

Explanation

`np=6 ` and npq=2 `rArr q=(1)/(3) " and " p=(2)/(3)`
`(nxx (2)/(3)) =6 rArr n= (6xx (3)/(2))=9`
`:. ` P(5 successes) `=.^(9)C_(5).((2)/(3))^(5) .((1)/(3))^(4)`