यदि ` y= (ax) ^((ax)^((ax)^...infty)),` तब सिद्ध कीजिये की
` " "(dy)/(dx) =(y^(2))/(x(1-ylog ax ))`

Explanation

` y= (ax)^(y) rArr " "log y= ylog ax `
`" "rArr " "(1)/(y)(dy)/(dx) =(dy)/(dx) log ax + y*(a)/(ax)`
अब सरल करने पर|