`int(sin(x-a))/(sin(x+a))dx` का मान ज्ञात कीजिए ।

Explanation

माना `" "I=int(sin(x-a))/(sin(x+a))dx`
और `" "x+a=t`
`rArr" "dx=dt`
`therefore" "=int(sin(t-2a))/(sint)dt`
`" "=int(sint.cos2a-costsin2a)/(sint)dt`
`" "=intcos2adt-intsin2a.cott dt`
`" "=tcos2a-sin2a.log|sint|+c`
`" "=(x+a)cos2a-sin2a log|sin(x+a)|+c`
`" "=xcos2a-sin2alog|sin(x+a)|c_(1)`
`" "`(जहाँ `c_(1)=c+acos2a` है )