`xlog 2x`

Explanation

`=log 2x int xdx - int [(d)/(dx)(log 2x)int xdx]dx`
`=(x^(2))/(2)log 2x- int((1)/(2x)xx2xx(x^(2))/(2)dx)`
`=(x^(2)log2x)/(2)-(1)/(2)int xdx`
`=(x^(2))/(2)log 2x-(1)/(4)x^(2)+C`