`x^(2)logx`

Explanation

`int x^(2)log x dx`
`=logx.intx^(2)dx-int{(d)/(dx)logx. Int x^(2)dx}dx`
(log x को प्रथम फलन लेने पर )
`=logx.(x^(3))/(3)-int(1)/(x).(x^(3))/(3)dx+C`
`=(x^(3))/(3)logx-(1)/(3).intx^(2)dx+C`
`=(x^(3))/(3)logx-(1)/(3).(x^(3))/(3)+C`
`=(x^(3))/(3)logx-(x^(3))/(9)+C`