`(cosx)/(sqrt(40sin^(2)x))`

Explanation

माना `I = int(cosx)/(sqrt(4-sin^(2)x))dx`
माना `" "sinx=t rArr cos x dx=dt`
`therefore" "I=int(1)/(sqrt(4-t^(2)))dt=sin^(-1)((t)/(2))+C`
`" "=sin^(-1)((sinx)/(2))+C`