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Which of the following metal in solution...

Which of the following metal in solution forms a precipitate with `NaOH` which is not soluble in an excess of the base?

A

Fe

B

Sn

C

Pb

D

Zn

Text Solution

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The correct Answer is:
A
Iron (Fe) metal in solution forms a red precipitate with NaOH and this precipitate is not soluble in an excess of the base.
`FeCl_(3)+3NaOHto underset("Ferric hydroxide (red ppt.)")(Fe(OH)_(3))+3NaCl`
White the precipitate of Sn, Pb, Zn are soluble in the excess of base.
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