In a triangle `ABC, a = 5, b = 7 and sinA = 3/4` how many such triangles are possible.

Options

A. 1
B. 0
C. 2
D. infinitely many

Answer

B

Explanation

a=5,b=7, `sinA=(3)/(4)`
`therefore("sin A")/(a)=("sin B")/(b)` gives
`sinB=(b)/(a).sinA=(7)/(5)xx(3)/(4)=(21)/(20)gt 1`
Impossible
`therefore` Therefore are not such triangles.