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The equation of the perpendicular bisect...

The equation of the perpendicular bisector of the line segment joining A(-2,3) and B(6,-5) is

A

x-y=-1

B

x-y=3

C

x+y=3

D

x+y=1

Text Solution

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The correct Answer is:
B
Mid-point of AB is
`((-2+6)/(2),(3-5)/(2))` i.e., `(2,-1)`
Slope of the line `AB=(-5-3)/(6+2)=-1`
So, slope of the required line is 1.
Hence, the requried equation of the line is given by
`y+1=1(x-2)`
`impliesy-x+3=0`
`impliesy-x+3=0`
`impliesx-y=3`
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