If the centre, one of the foci and semi-major axis of an ellipse are (0,0), (0,3) and 5, then its equation is

Options

A. `(x^(2))/(16)+(y^(2))/(25)=1`
B. `(x^(2))/(25)+(y^(2))/(16)=1`
C. `(x^(2))/(9)+(y^(2))/(25)=1`
D. None of these

Answer

A

Explanation

We have, b=5 and bgta
Since, `c^(2)=b^(2)-a^(2)`
`impliesa^(2)=16`
`therefore` Required equation of ellipse is
`(x^(2))/(16)+(y^(2))/(25)=1`