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Equation of unit circle concentric with ...

Equation of unit circle concentric with circle
`x^(2)+y^(2)+8x+4y-8=0` is

A

`x^(2)+y^(2)+8x+4y+19=0`

B

`x^(2)+y^(2)-8x+4y+19=0`

C

`x^(2)+y^(2)-8x-4y+19=0`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A
`because` `g=4,f=2,c=-8`
`therefore` Centre=(-4,-2)=Centre of concentric circle
Also, radius of unit circle=1
`therefore` Required equation of circle is
`(x+4)^(2)+(y+2)^(2)=1`
`impliesx^(2)+y^(2)+8x+4y+19=0`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 05-Paper 2 (Mathematics)
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