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Three numbers are chosen from 1 to 20. F...

Three numbers are chosen from 1 to 20. Find the probability that they are consecutive.

A

`(1)/(190)`

B

`(1)/(120)`

C

`(3)/(190)`

D

`(5)/(190)`

Text Solution

Verified by Experts

The correct Answer is:
C
The total number of favourable cases, n(E)=18
The total number of cases,
`n(S)=.^(20)C_(3)`
`=(20xx19xx18)/(3xx2xx1)=1140`
`therefore` Required probability
`=(18)/(1140)=(3)/(190)`
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