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The general solution of |sinx|=cosx is (...

The general solution of `|sinx|=cosx` is (When `ninz`) given by

A

`npi+(pi)/(4)`

B

`2npi+-(pi)/(4)`

C

`n pi+-(pi)/(4)`

D

`npi-(pi)/(4)`

Text Solution

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The correct Answer is:
B
Given, `|sinx|=cosx`
`thereforesin^(2)x=cos^(2)x`
`implies2cos^(2)x=1`
`impliescosx=+(1)/(sqrt(2))`
[`because` x cannot be negative]
`impliesx=2npi+-(pi)/(4)`
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