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The sum of all two digit natural numbers...

The sum of all two digit natural numbers which leave a remainder 5 when they are divided by 7 equal to

A

715

B

702

C

615

D

602

Text Solution

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The correct Answer is:
B

Required two digit numbers are 12,19,. . .,96 which leave a remainer 5 when they are divided by 7.
Here, `a=12,d=7,l=96`
`thereforel=a+(n-1)d`
`implies96=12+7(n-1)`
`impliesn=13`
`thereforeS_(13)=(13)/(2)(12+96)`
`=(13xx108)/(2)=702`
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