The ionization energy for the hydrogen atom is `13.6 eV` then calculate the required energy in `eV` to excite it from the ground state to `1^(st)` excited state.

Options

A. 3.4 eV
B. 10.2 eV
C. 12.1 eV
D. 1.5 eV

Answer

B

Explanation

As, we know that energy of hydrogen atom in `n^(th)` level is given by
`E_(n)=(-13.6)/(n^(2))"eV"`
The energy in first excited state (n = 2)
`=(-13.6)/((2)^(2))`
`=-3.4" eV"`
Thus, energy required to excite it form ground state to the next higher state is
`=E_(2)-E_(1)=-3.4-(-13.6)`
`=10.2" eV"`