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If tanbeta=costhetatanalpha, then "tan...

If `tanbeta=costhetatanalpha`, then `"tan"^(2)(theta)/(2)`=

A

`(sin(alpha+beta))/(sin(alpha-beta))`

B

`(cos(alpha-beta))/(cos(alpha+beta))`

C

`(sin(alpha-beta))/(sin(alpha+beta))`

D

`(cos(alpha+beta))/(cos(alpha-beta))`

Text Solution

Verified by Experts

The correct Answer is:
C
`"tan"^(2)(theta)/(2)=(1-costheta)/(1+costheta)=(tanalpha-tanbeta)/(tanalpha+tanbeta)=(sin(alpha-beta))/(sin(alpha+beta))`
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  11. If tanA-tan B=x, and cot B-cotA=y, then find the value of cot(A-B).

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